UC知道数学题～～～～～～～～～～～～～～～～～～
来源：百度知道 编辑：UC知道 时间：2024/06/28 00:24:11
cot(A+B)=cotAcotB-1\cotA+cotB
sin(A+B)\sin(A-B)=tanA+tanB\tanA-tanB
cos(A+B)\cos(A-B)=1-tanAtanB\1+tanAtanB
((cos5 π) \12)+(sin5 π) \12)\((cos π)\12)-(sin π )\12
sin5+sin t \cos s +cos t =tan(s+t)\2
sin 2x \sin x -cos2x\cos x =sec x
sin4X=(3-4cos2x+cos4X)\8
sin3x=3sinx-4sin^3x
5+7cos2x=3cosx=cos2xcos4x
sin(A+B)\sin(A-B)=tanA+tanB\tanA-tanB
cos(A+B)\cos(A-B)=1-tanAtanB\1+tanAtanB
((cos5 π) \12)+(sin5 π) \12)\((cos π)\12)-(sin π )\12
sin5+sin t \cos s +cos t =tan(s+t)\2
sin 2x \sin x -cos2x\cos x =sec x
sin4X=(3-4cos2x+cos4X)\8
sin3x=3sinx-4sin^3x
5+7cos2x=3cosx=cos2xcos4x
cot(A+B)=1\tan(A+B)
=(1-tanAtanB)\(tanAtanB)
=[1-1\(cotAcotB)]\(1\cotA+1\cotB)
=[(cotAcotB-1)\(cotAcotB)]\[(cotA+cotB)\(cotAcotB)]
=(cotA-cotB-1)\(cotA=cotB)
sin(A+B)\sin(A-B)=(sinAcosB+cosAsinB)\(sinAcosB-cosAsinB)
=(tanA+tanB)\(tanA-tanB)
cos(A+B)\cos(A-B)=(cosAcosB-sinAsinB)\(cosAcosB+sinAsinB)
=(1-tanAtanB)\(1+tanAtanB)
[(cos5π)\12+(sin5π)\12]\[(cosπ)\12)-(sinπ)\12]=(cosπ+sinπ)\(cosπ-sinπ)
=(-1+0)\(-1-0)
=1
cot(A+B)=1\tan(A+B)
=(1-tanAtanB)\(tanAtanB)
=[1-1\(cotAcotB)]\(1\cotA+1\cotB)
=[(cotAcotB-1)\(cotAcotB)]\[(cotA+cotB)\(cotAcotB)]
=(cotA-cotB-1)\(cotA=cotB)
sin(A+B)\sin(A-B)=(sinAcosB+cosAsinB)\(sinAcosB-cosAsinB)
=(tanA+tanB)\(tanA-tanB)