x+1/x=c+1/c解为x=c或1/c.x+2/x=c+2/c解为x=c或2/c所以x+2/(x-1)=a+2/(a-1)解为？

左右两边有相同的格式；

x+m/x=c+m/c ===>解是x(1)=c x(2)=(m)/c

所以：x+2/(x-1)=a+2/(a-1)解为：

（x-1)+2/(x-1)=(a-1)+2/(a-1)

x-1=a-1===>x=a

x-1=2/(a-1)===>x=2/(a-1)+1=(a+1)/(a-1)

方程两边同时减1得X-1的解为a-1或2/(a-1)
所以方程的解为a或(a+1)/(a-1)