(1+sin2α+cos2α)/(1-sin2α+cos2α)=什么

用什么合比，用sin化半角和cos化半角的公式。相信我没错！！

(1+sin2α)/cos2α=cos2α/(1-sin2α)
由合比性质知
(1+sin2α)/cos2α=(1+sin2α+cos2α)/(cos2α+1-sin2α)

(1+sin2α)/cos2α
=(sin²α+cos²α+2sinαcosα)/(cos²α-sin²α)
=(cosα+sinα)²/[(cosα-sinα)(cosα+sinα)]
=(cosα+sinα)/(cosα-sinα)
=(1+tanα)/(1-tanα)
=(tan45+tanα)/(1-tan45*tanα)
=tan(45+α)

(1+sin2α+cos2α)/(1-sin2α+cos2α)
=(1+sin2α)/cos2α
=tan(45+α)

=1/cos2α+tan2α

=tan(45+α)