(81.4+1/6+1/4+1/5)/(1/4+1/5+1/6) = 133 求过程

来源：百度知道编辑：UC知道时间：2024/06/27 14:47:04

(81.4+1/6+1/4+1/5)/(1/4+1/5+1/6) = 133
计算过程是什么呀？

(81.4+1/6+1/4+1/5)/(1/4+1/5+1/6) =[81.4/(1/4+1/5+1/6)]+1
=[(407/5)/(1/4+1/5+1/6)]+1
=132+1=133

(81.4+1/6+1/4+1/5)/(1/4+1/5+1/6)
=[81.4+(20/120+30/120+24/120)]/(20/120+30/120+24/120)
=(81.4+74/120)/(74/120)
=132+1
=133

(81.4+1/6+1/4+1/5)/(1/4+1/5+1/6) =[81.4/(1/4+1/5+1/6)]+1
=[(407/5)/(1/4+1/5+1/6)]+1
=132+1=133

(81.4+1/6+1/4+1/5)/(1/4+1/5+1/6)
=[81.4+(20/120+30/120+24/120)]/(20/120+30/120+24/120)
=(81.4+74/120)/(74/120)
=132+1
=133

或者直接用计算器算了

以上的都是高手

1+1/3+1/6+........+1/55 5/6=1/?+1/?+1/? (1/2) (1/4+1/6)= 1/2 ，1/3 ,1/6 /1/6 ,() 1/2+1/6+1/12+1/20+1/30 1/6+1/8+1/10+1/12+..........+1/202=? 1/2+1/4+1/6+1/8+.......+1/n=? -1/2-1/6-1/12-1/20-``````````````-1/4026042 1/2+1/6+1/12+......+1/1980+1/2070=? (1/2-1)*(1/3-1)*(1/4-1)*(1/5-1)*(1/6-1)*(1/7-1)*(1/8-1)*(1/9-1)*(1/10-1)