C++构造函数调用问题???在线等??

来源:百度知道 编辑:UC知道 时间:2024/07/08 00:43:48
class A
{public:
A (int i)
{a=i;cout<<"called".<<a<<endl;}
~A()
{cout<<"call".<<a<<endl;}
void print ()
{cout<<a<<',';}
int Geta ()
{ return a;}
private:
int a;
};
class B :public A
{ pubilc:
B(int i,int j,int k) :A(i),aa(j)
{b=k;cout<<"called",<<b<<endl;}
~B()
{cout<<"call".<<b<<endl;}
void print()
{A::print();
cout<<b<<','<<aa.Geta()<<endl;}
private:
int b;int a;
};
void main()
{
B bb[2];
bb[0]=B(7,8,9)
bb[1]=b(12,13,14)
for(inti=0;i<2;i++)
bb[i].print();
}
程序结果是called.7
called.8
called.9
call.9

贴的代码B构造中aa是咋回事?
代码只看就发现有多处错误
A (int i){a=i;cout<<"called".<<a<<endl; } //"called". ??
~A(){cout<<"call".<<a<<endl;} //"call".??
{b=k;cout<<"called",<<b<<endl;} //"called", ??
///...

我找遍也没有发现aa在那里定义的,先把你的程序搞对了,然后再把运行结果弄上来分析吧。