脱式计算:(4/5-7/25)除[1/4-20%(1+25%)+2%] (求计算过程)

来源:百度知道 编辑:UC知道 时间:2024/07/05 06:04:52

(4/5-7/25)/[1/4-20%(1+25%)+2%]
=(20/25-7/25)/[1/4-(1/5)*(5/4)+2%]
=(13/25)/(1/4-1/4+1/50)
=(13/25)/(1/50)
=(13/25)*50
=26

解原式=(20/25-7/25)/[1/4-1/5*(1+1/4)+1/50]
=(13/25)/(1/4-1/5*5/4+1/50)
=(13/25)/(1/4-1/4+1/50)
=13/25*50
=26

(4÷5-7÷25)÷(1÷4-20%(1+25%)+2%)
=(20÷25-7÷25)÷(25%-25%+2%)
=(13÷25)÷2%
=13/25×50
=26

(4/5-7/25)/[1/4-20%(1+25%)+2%]
=(20/25-7/25)/(25/100-25/100+2/100)
=(13/25)/(2/100)
=(13/25)×50
=26
脱式的关键是:找出同分母,以便于加减运算

原式=(20/25-7/25)÷[1/4-20/100-(20×25)/(100×100)100+2/100] 先去掉小括号
=(13/25)÷[25/100-20/100-5/100+2/100] 再去中括号
=(13/25)÷(25-20-5+2)/100
=(13/25)÷(2/100) 除号变乘号
=(13/25)×50 除数打颠倒
=2×13
=26

是除还是除以?除和除以的意思不一样,去想你是打错了