初二数学题（很简单）

来源：百度知道 编辑：UC知道 时间：2024/09/22 13:34:53
(4x^2)/(4y^2-x^2)+4y^2/(x-2y)+x+2y
[麻烦写过程！]

x+2y+(4y^2)/(x-2y)+(4x^2y)/(4y^2-x^2)
= [(x+2y)(x-2y)+4y^2]/(x-2y)+(4x^2y)/(4y^2-x^2)
= x^2/(x-2y)+(4x^2y)/(4y^2-x^2)
= x^2(x+2y)/(x^-4y^2)-4x^2y/(x^2-4y^2)
= (x^3-2x^2y)/(x^2-4y^2)
= x^2(x-2y)/(x+2y)(x-2y)
= x^2/(x+2y)

晕,大学读读就看不懂你写的什么东西了!呵呵~~~~~~

笨蛋

原式= [(x+2y)(x-2y)+4y^2]/(x-2y)+(4x^2y)/(4y^2-x^2)
= x^2/(x-2y)+(4x^2y)/(4y^2-x^2)
= x^2(x+2y)/(x^-4y^2)-4x^2y/(x^2-4y^2)
= (x^3-2x^2y)/(x^2-4y^2)
= x^2(x-2y)/(x+2y)(x-2y)
= x^2/(x+2y)

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