代数题 谢谢了!!

x=[(√5)-1]/2
√5=2x+1
两边平方
4x^2+4x+1=5
x^2+x=1
x^4 + x^2 + 2x - 1
=x^4+x^3-x^3+x^2+2x-1
=x^2(x^2+x)-x^3+x^2+2x-1
=x^2*1-x^3+x^2+2x-1
=-x^3+2x^2+2x-1
=-x^3-x^2+3x^2+2x-1
=-x(x^2+x)+3x^2+2x-1
=-x*1+3x^2+2x-1
=3x^2+x-1
=3(x^2+x)-2x-1
=3*1-2x-1
=-2x-2
=-2*(√5-1)/2-2
=2√5

(x-1)(x-2)(x-3)(x-4)
=[(x-1)(x-4)][(x-2)(x-3)]
=[(x^2-5x)+4][(x^2-5x)+6]
=(x^2-5x)^2+10(x^2-5x)+24
=x^4-10x^3+25x^2+10x^2-50x+24
=x^4-10x^3+35x^2-50x+24

[x(√x) + x(√y)]/(xy - y^2)-[x+(√xy)+y]/[x(√x)-y(√y)]
=x(√x+√y)/[y(x-y)]-[x+(√xy)+y]/[(√x)^3-(√y)^3]
=x(√x+√y)/[y(x-y)]-[x+(√xy)+y]/[(√x-√y)(x+√xy+y)]
=x(√x+√y)/[y(√x+√y)(√x-√y)]-1/[(√x-√y)
=x/[y(√x-√y)]-y/[y(√x-√y)
=(x-y)/[y(√x-√y)]
=(√x+√y)(√x-√y)/[y(√x-√y)]
=(√x+√y)/y

你是要过程呢还是只要结果？这应该是暑假作业吧？自己不动脑了？