当n趋向于无穷大时,limf(x)=n^100/{n^k+n^(k-1)}=A且A不等于0时求A及K

来源:百度知道 编辑:UC知道 时间:2024/06/30 19:53:50
当n趋向于无穷大时,limf(x)=n^100/{n^k+n^(k-1)}=A且A不等于0时求A及K

n→+∞时:

A = lim{n^100/[n^k+n^(k-1)]}
= lim{1/[n^(k-100)+n^(k-101)]} = 无极限 ......n<100
= 1 ...........n =100
= 0 ...........n>100
∵极限 = A≠0--->n=100,A=1

K=100
A=1

f(x)=n^100/[n^k+n^(k-1)]=1/[n^(k-100)+n^(k-101)] A不等于令 所以 只有n^(k-100)=1 k=100 A=1

A=1 K=100