初一乘方运算题,速度

来源:百度知道 编辑:UC知道 时间:2024/09/27 19:21:43
(1)-3/4×[-3的2次方×(-2/3)的2次方-2]

(2)-1.6÷[(-2/3)的2次方×(-3)的3次方-2的2次方]

(3)3的2次方-(-6.5)×4/13+(-2)的4次方÷[(-2)的3次方+4]

(4)3的2004次方

1. -3/4*[-9*(4/9)-2]
=-3/4*(-6)
=9/2

2. =-1.6/[(4/9)*(-27)-4]
=-1.6/(-12-4)
=-1.6/(-16)
=0.1

3. =9+6.5*(4/13)+16/(-8+4)
=9+2+16/(-4)
=9+2-4
=7

4. 3^2004
不用处理。

1)-3/4×[-3的2次方×(-2/3)的2次方-2]

. -3/4x[-9x(4/9)-2]
=-3/4x(-6)
=9/2

(2)-1.6÷[(-2/3)的2次方×(-3)的3次方-2的2次方]
=-1.6/[(4/9)x(-27)-4]
=-1.6/(-12-4)
=-1.6/(-16)
=0.1

(3)3的2次方-(-6.5)×4/13+(-2)的4次方÷[(-2)的3次方+4]
=9+6.5*(4/13)+16/(-8+4)
=9+2+16/(-4)
=9+2-4
=7

(4)3的2004次方
=3^2004

(1)
-3/4×[-3的2次方×(-2/3)的2次方-2]
=-3/4×[-9×4/9-2]
=-3/4×[-4-2]
=-3/4×-6
=9/2
(2)
-1.6÷[(-2/3)的2次方×(-3)的3次方-2的2次方]
=-1.6÷[4/9×-27-4]
=-1.6÷[-12-4]
=-1.6÷-16
=1/10
(3)
3的2次方-(-6.5)×4/13+(-2)的4次方÷[(-2)的3次方+4]
=9-(-2)+16