1/45+1/117+1/221+...+1/101*105=?????
来源:百度知道 编辑:UC知道 时间:2024/09/27 19:22:03
#include <cstdlib>
#include <iostream>
using namespace std;
int main(int argc, char *argv[])
{
int i;
double s;
i=5;
while(i<=101)
{
s=s+1/(i*(i+4));
cout<<i<<" "<<i*(i+4)<<" "<<s<<endl;
i=i+4;
}
system("PAUSE");
return EXIT_SUCCESS;
}
结果为:5.28418e-308
原式=1/(5*(5+4))+1/(9*(9+4))+...+1/(101*(101+4))
=0.25*(1/5-1/105)
=1/21
1/3+1/5+1/7+1/9+1/11+1/33+1/35+1/45+1/55+1/77=?
1/3+1/5+1/7+1/9+1/11+1/33+1/35+1/45+1/55+1/77
1/3+1/6+1/10+1/15+1/21+1/28+1/36+1/45=? (算式中都是分数)怎样用简便方法计算?
[14.8+(37/2-1.5)*125/3]/45/1
1/( )+1/( )+1/( )+1/( )+1/( )+1/( )=1
求救:如果1/a+1/b+1/c+1/d+1/35+1/45=1 求a+b+c+d的值
已知(a/1+b/1+c/1+d/1)+36/1+45/1=1且a,b,c,d是4个连续自然数,求a+b+c+d的值.怎么算???
1/8=1/( )+1/( )1 1/10=1/( )+1/( )1/12=1/( )+1/( )+1/( )
(1/2005-1)(1/2004-1)........(1/3-1)(1/2-1)
(1-1/100)(1-1/99)(1-1/98)......(1-1/3