某一道数学题

来源:百度知道 编辑:UC知道 时间:2024/07/05 22:45:59
x+y+z-根号x-根号y-根号z+3/4=0 求XYZ的值

x+y+z-根号x-根号y-根号z+0.75=0
(x-根号x+1/4)+(y-根号y+1/4)+(z-根号z+1/4)=0
(根号x-1/2)^2+(根号y-1/2)^2+(根号z-1/2)^2=0
所以根号x=根号y=根号z=1/2
所以x=y=z=1/4

X-genhaoX+1/4+y-genhaoY+1/4+Z-genhaoZ+1/4=0
(genhaoX-1/2)+(genhaoY-1/2)+(genhaoZ-1/2)=0
X=Y=Z=1/4

x+y+z-根号x-根号y-根号z+3/4=(根号x-0.5)^2+(根号x-0.5)^2+(根号x-0.5)^2=0,所以 根号x=根号y=根号z=0.5
答案就显然啦