因式分解：（1）x3-x2+3x-3 (2)6xy-10+15x-4y (3)5ax2-b2-b2x+5ax

(1) x3-x2+3x-3
=(x^3+3x)-(x^2+3)
=x(x^2+3)-(x^2+3)
=(x^2+3)(x-1)

(2)6xy-10+15x-4y
=(6xy+15x)-(4y+10)
=3x(2y+5)-2(2y+5)
=(2y+5)(3x-2)

(3)5ax2-b2-b2x+5ax
=(5ax^2+5ax)-(b^2x+b^2)
=5ax(x+1)-b^2(x+1)
=(x+1)(5ax-b^2)

1.原式=x(x2-1)+3(x-1)
=x(x+1)(x-1)+3(x-1)=3x(x+1)(x-1)
2.原式=3x(5+2y)-2(5+2y)=(5+2y)(3x-2)
3.原式=5ax(x+1)-b2(x+1)=(x+1)(5ax-b2)

（3X-2)(2Y+5)

1.原式=X^2*(X-1)＋3*(X-1)=(X-1)*(X^2+3) 2.原式＝(6*X*Y-*4Y)+(15*X-10)=2*Y(3*X-2)+5*(3*X-2)=(3*X-2)(2*Y+5) 3.原式＝(5a*x^2+5a*x)-(b*2+b*2*x)=(5a*x-b*2)(x+1)