高一数学题化简

来源：百度知道 编辑：UC知道 时间：2024/09/20 03:54:49
sin50°{1+(跟3)tan10°}

sin50(1+√3tan10 )=sin50(1+tan60tan10)=sin50(1+sin60sin10/cos60cos10)
=sin50[(cos60cos10+sin60sin10)/cos60cos10]
=sin50[cos50/cos60cos10]
=2sin50cos50/2cos60cos10
=sin100/cos10
=cos10/cos10
=1
注：√3是跟3的意思

sin50°(1+√3tan10° )
=sin50°(1 + sin60°sin10°/cos60°cos10°)
=sin50°[(cos60°cos10°+ sin60°sin10°)/cos60°cos10°]
=sin50°[cos50°/cos60°cos10°]
=2sin50°cos50°/2cos60°cos10 °
=sin100°/cos10 °
=cos10°/cos10 °
=1