繁分数,方程

[(1又x\28+20又47\112)\5-4又2\21*0.75]除以(1\3+5\7*14)\[(4-2又2\3)*3=4.5
[(1+x\28)+(20+47\112)]\5-(4+2\21)*0.75]÷{(1\3+10)\[4-(2+2\3)]*3}=4.5
[(21+x\28+47\112)\5-(4*0.75+2\21*0.75)]÷{(31\3)\(12-6-2)}=4.5
21\5+x\140+47\560-3-1/14=4.5*31\12
x\140+97\80=93/8
x\140=93\8-97\80=833\80
x=(833\80)*140=5831\4