6lg20+3lg25等于多少。要过程。在线等

6lg20+3lg25
=6(lg2+lg10)+3lg5^2
=6lg2+6lg10+6lg5
=6(lg2+lg5)+6lg10
=6lg10+6lg10
=12lg10
=12

6lg20+3lg25=6lg(5*4)+3lg(5^2)
=6lg5+6lg4+6lg5=12lg5+6lg(2^2)=12lg5+12lg2 = 12lg(5*2)= 12
很高兴为你解决问题！

6lg20+3lg25=6lg20+3lg（5^2)
=6lg20+6lg5
=6(lg20+lg5)
=6lg(20*5)
=6lg100
=6*2
=12

6lg20+3lg25=6(lg2+lg10)+3×2（lg10-lg2）

=6lg2+6+6-6lg2

=12

6lg20+3lg25=6(2lg2+lg5)+6lg5=12lg2+12lg5=12lg10=12