1点40前急等..数学..

来源：百度知道 编辑：UC知道 时间：2024/07/05 07:06:33
-（X^4)^5=?
[(-X)^4]^2=
-(b^2+3)^3=
(a^n-2）^2 ·(a^n+1)^3
[(x+y)^2]^3·[(x+y)^3]^4
后3题要过程..

-（X^4)^5=-X^20

[(-X)^4]^2= X^8

-(b^2+3)^3= -B^6-9B^4-27B^2-27

(a^n-2）^2 ·(a^n+1)^3 =a^6n+3a^5n-a^4n-4a^3n+12a^2n+24a^n+4

[(x+y)^2]^3·[(x+y)^3]^4 =(x+y)^18

-X^20
X^8
a^(5n-1)
(x+y)^18

1.-X^20
2.X^8
3.原式=-(b^2+3)^2*(b^2+3)=-(b^4+6*b^2+9)*(b^2+3)=-(b^6+9*b^4+27*b^2+27)

书写过程太麻烦了……

-X^20
X^8
-b^6—9
(a^2n-4)*(a^3n+1)
[(x+y)^6]*[(x+y)^12]=(x+y)^18