2道代数奥数题

来源:百度知道 编辑:UC知道 时间:2024/09/22 19:25:13
1、
已知a是方程x^2-3x+1=0的根,求2a^2-5a-2+3/(a^2+1)的值
2、
(1/(1+√2))+(1/(√2+√3)))+(1/(√3+√4))+……(1/(√2006+√2007))+(1/(√2007+√2008))=?
要写过程,并且第一个作出两道题的为答案

1. X^2=3X-1则原式=2(3a-1)-5a+3/3a
=6a-2-5a+1/a
=a-2+1/a=(a^2+1)/a-2=3-2=1
2. 1/(1+√2)+1/(√2+√3)+1/(√3+√4)+......+1/(√n+√n+1)
=√2-1+√3-√2+√4-√3+...+√(n+1)-√n
=-1+√(n+1)
(1/(1+√2))+(1/(√2+√3)))+(1/(√3+√4))+……(1/(√2006+√2007))+(1/(√2007+√2008))=-1+√2008

1. X^2=3X-1则原式=2(3a-1)-5a+3/3a
=6a-2-5a+1/a
=a-2+1/a=(a^2+1)/a-2=3-2=1

X^2=3X-1则原式=2(3a-1)-5a+3/3a
=6a-2-5a+1/a
=a-2+1/a=(a^2+1)/a-2=3-2=1

用写过程么