UC知道关于线虫的遗传题，高手请进
来源：百度知道 编辑：UC知道 时间：2024/06/28 11:08:34
C. elegans nematodes exist as self-fertilizing hermaphrodites with two X chromosomes (XX) and males with only one X chromosome (XO). Normally, hermaphrodites produce only XX self progeny hermaphrodites. A mutation in the autosomal gene him-8 (high incidence of males) gene causes frequent X-chromosome non-disjunction events during meiosis, creating nullo-X gametes and resulting in many male (XO) progeny. unc-18 is a gene on the X chromosome; mutations in it cause animals to be uncoordinated. dpy-17 is a gene on chromosome III; mutations in it cause animals to be dumpy. Mutations in unc-18, dpy-17 and him-8 are all recessive. If wild-type males are crossed into hermaphrodites that are homozygous for all three mutations. what types of phenotypes will you see among the cross progeny?
wild-type males and hermaphrodites
uncoordinated males and hermaphrodites
uncoordinated males and wild-type hermaphrodites
wild-type males and uncoordinated hermaphrodites
a and
wild-type males and hermaphrodites
uncoordinated males and hermaphrodites
uncoordinated males and wild-type hermaphrodites
wild-type males and uncoordinated hermaphrodites
a and
先翻译下好理解：
作为自交雌雄同体线虫存在两个X染色体(XX)和雄性只用一个X染色体(XO)。通常,雌雄同体只产生同样的雌雄同体XX。由于染色体基因him-8(雄性高发)在减数分裂中造成频繁的X-染色体不分离，产生0-X配子（即没有X）,且很多雄性(XO)子代.unc-18 是X染色体上的一个基因。突变导致动物不协调的（这个uncoordinated翻译是否正确？不育？）. dpy-17是3号染色体上的一个基因，它突变会导致动物变得粗胖。突变unc-18 dpy-17和him-8,都是隐性的。如果野生雄性与雌雄同体杂交，会产生这三种突变的纯合子.你会看到在交配后代是什么类型的表现型?
野生的雄性和雌雄同体
不协调的雄性和雌雄同体
不协调的雄性和野生雌雄同体
雄性和不协调雌雄同体野生
a和b
分析：
x （♂） 与 XX （♀）杂交
x （♂）为野生型，其基因中不含3中突变基因
XX （♀）含3种突变基因
产生后代有：
Xx,X0,x0
即雌雄同体（Xx），不协调雄性（X0），野生雄性（x0）
这样我选a and b
我的水平只能解释到这个地步，如果错误请高手指正