帮我解两题分式方程...！！！

来源：百度知道 编辑：UC知道 时间：2024/09/25 23:22:14
我要有过程的！
1）1/X-2 + 1/X-6 = 1/X-7 + 1/X-1

2）X-4/X-5 - x-5/x-6 =x-7/x-8 - x-8/x-9

1)）1/X-2 + 1/X-6 = 1/X-7 + 1/X-1
(X-6+X-2)/(X方-8X+12)=(X-1+X-7)/(X方-8X+12)
(2X-8)/(X方-8X+12)=(2X-8)/(X方-8X+12)
则X不等于1,2,6,7

2）X-4/X-5 - x-5/x-6 =x-7/x-8 - x-8/x-9
(X-5+1)/(X-5)-(X-6+1)/(X-6)=(X-8+1)/(X-8)-(X-9+1)/X-9)
1+1/(X-5)-1-1/(X-6)=1+1/(X-8)-1-1/(X-9)
1/(X-5)-1/(X-6)=1/(X-8)-1/(X-9)
1/(X-5)+1/(X-9)=1/(X-6)+1/(X-8)
(X-9+X-5)/(X方-14X+45)=(X-8+X-6)/(X方-14X+48)
则2X-14=0 X=7