8年级公因式题
来源:百度知道 编辑:UC知道 时间:2024/09/22 14:40:45
3a^2-3b^2
y^2-9(x+y)^2
要详细过程 麻烦大家了
y^2-9(x+y)^2
要详细过程 麻烦大家了
3a^2-3b^2
=3(a^2-b^2)
=3(a+b)(a-b)
y^2-9(x+y)^2
=(y+3(x+y))(y-3(x+y))
=(3x+4y)(-3x-2y)
3(a^2-b^2)=3(a+b)(a-b)
y^2-9(x+y)^2 =y^2-(3x+3y)^2=(y+3x+3y)(y-3x-3y)=-(3x+2y)(3x+4y)
楼主竟然知道^表示次幂
3a^2-3b^2
=3(a^2-b^2)
=3(a-b)(a+b)
y^2-9(x+y)^2
=(y-3x-3y)(y+3x+3y)
=-(3x+2y)(3x+4y)
3a^2-3b^2=3(a^2-b^2)=3(a-b)(a+b)
y^2-9(x+y)^2=[y-3(x+y)][y+3(x+y)]=-(3x+2y)(3x+4y)
y^2-9(x+y)^2
=y^2-9x^2-18xy-9y^2
=-(9x^2+18xy+8y^2)
=-(3x+2y)(3x+4y)
回答者: 我是陈光华 - 举人 四级 3-15 18:34
3a^2-3b^2
=3(a^2-b^2)
=3(a+b)(a-b)
y^2-9(x+y)^2
=(y+3(x+y))(y-3(x+y))
3a^2-3b^2
=3(a^2-b^2)
=3(a-b)(a+b)
y^2-9(x+y)^2
=(y-3x-3y)(y+3x+3y)
=(-3x-2y)(3x+4y)