解一个一元一次方程

(480-96)/x+96/(8+x)=480/(x+4)
384/x+96/(8+x)=480/(x+4)
384(x+8)(x+4)+96x(x+4)=480x(x+8)
4(x+8)(x+4)+x(x+4)=5x(x+8)
(x+4)[4(x+8)+x]=5x(x+8)
(x+4)(5x+32)=5x(x+8)
5x^2+52x+128=5x^2+40x
5x^2+52x+128-5x^2-40x=0
12x+128=0
3x+32=0
x=-32/3
经检验,x=-32/3是原方程的根。

(480-96)/x+96/(8+x)=480/(x+4)
[通分：]384(8+x)(x+4)+96x(x+4)=480x(8+x)
384(8x+32+x^2+4x)+96(x^2+4x)=480(x^2+8x)
3072x+12288+384x^2+1536x+96x^2+384x=480x^2+3840x
-8x^2+1152x+12288=0
x^2+144x+1536=0
X1=-11.6
X2=-132.4

480-96)/x+96/(8+x)=480/(x+4)
[通分：]384(8+x)(x+4)+96x(x+4)=480x(8+x)
384(8x+32+x^2+4x)+96(x^2+4x)=480(x^2+8x)
3072x+12288+384x^2+1536x+96x^2+384x=480x^2+3840x
-8x^2+1152x+12288=0
x^2+144x+1536=0
X1=-11.6
X2=-132.4

480-96)/x+96/(8+x)=480/(x+4)
384/x+96/(8+x)=480/(x+4)
384(x+8)(x+4)+96x(x+4)=480x(x+8)
4(x+8)(x+4