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来源：百度知道 编辑：UC知道 时间：2024/07/06 17:18:59
In order to estimate the negative relationship between initial commitment and voluntary turnover with greater statistical accuracy and efficiency than with correlations and t-tests, the survival analysis analog to regression was calculated. In agreement with traditional methods, the survival coefficient indicated a significant negative effect of initial commitment on voluntary turnover (b=.42, Z=-5.47, p<05), and the log likelihood function indicated a significant survival equation (likelihood= -1144.02, chi-squared=30.13, p<05). Because survival coefficients are expressed as logarithmic functions, simple arithmetic conversions to a normal, base-ten metric are normally required before interpretation. Accordingly, the conversion to normal values produced .66, which means that, on average, those cadets who were one standard deviation above the mean on initial commitment had a turnover rate that was approximately 66% lower than those individuals with average initial commitment. In s

为了较大统计的准确性和效率与相比有的相互关系和t--检验-地估计负的开头承诺和自愿周转之间的关系,救生分析退回was的类似物计算.同意传统方法,救生协同因素指示一开头的对的承诺的重要的负的对自愿周转((b=.42,Z=-5.47,p<05)的影响,和原木可能性功能指示一重要救生等式((likelihood=-1144.02,chi-squared=30.13,p<05).因为救生协同因素是对数函数功能被表达,不做作的算术的转换成一正常,无价值-十米的公亩在一般情况下要求以前的事物解释.相应地,转换成正常价值观生产.66,其意味着平均起来,那些是在有关开头承诺中间状态之上一均方差的学员有一换手率那是的大约66%较低与相比那些个体用平均为用缩写名签承诺.概言之,救生coefficent证明一实质性的开头承诺和随后周转之间的关系.

为了估计负面关系初步的承诺和自愿营业额以更大的统计精度和效率的相关性比和T -试验，模拟的生存，以回归分析，计算。在与传统方法相比，生存系数表明了重大负面影响的初步承诺自愿更替（二=. 42口=- 5.47 ，磷“ 05 ） ，以及对数似然函数表示了重大的生存方程（然= - 1144.02 ，卡方= 30.13 ，磷“ 05 ） 。由于生存系数是表示对数功能，简单的算术转换到正常，基站10公吨之前通常需要解释。因此，转换为正常价值产生0.66 ，这意味着，平均而言，这些学员谁是1个标准差以上，平均上初步承诺的流失率是大约66 ％低于个人平均初步承诺。总之，生存系数表现出很大关系，初步的承诺和后来的营业额