求程序：输入日期就能查出星期几？

来源：百度知道 编辑：UC知道 时间：2024/09/21 13:34:48
int f(int sum)
{
int year,month,day,leap;
switch(month)
{
case 1:sum=0;break;
case 2:sum=31;break;
case 3:sum=59;break;
case 4:sum=90;break;
case 5:sum=120;break;
case 6:sum=151;break;
case 7:sum=181;break;
case 8:sum=212;break;
case 9:sum=243;break;
case 10:sum=273;break;
case 11:sum=304;break;
case 12:sum=334;break;
default:printf("data error\n");break;
}
sum=sum+day;
if(((year%100)&&(year%400))||(year%4))
leap=1;
else
leap=0;
if(leap==1&&month>2)
sum++;
return sum;

}
main()
{
int year,month,day,A,B,C,sum;
printf("input year,month,day:\n");
scanf("%d %d %d",&year,&month,&day);
A=f(sum);
B=year-1+(year-1)/4+(year-1)/400-(year-1)/100+A;
C=B%7;
switch(C)
{
case

你在定义形式参数的时候有点问题，实参中的month不能传递给switch的month.
我用的是VC++
我给你改了一下：
#include<stdio.h>
int f(int sum,int month)
{
int year,day,leap;
switch(month)
{
case 1:sum=0;break;
case 2:sum=31;break;
case 3:sum=59;break;
case 4:sum=90;break;
case 5:sum=120;break;
case 6:sum=151;break;
case 7:sum=181;break;
case 8:sum=212;break;
case 9:sum=243;break;
case 10:sum=273;break;
case 11:sum=304;break;
case 12:sum=334;break;
default: printf("data error\n");break;
}
sum=sum+day;
if(((year%100)&&(year%400))||(year%4))
leap=1;
else
leap=0;
if(leap==1&&month>2)
sum++;
return sum;

}
main()
{
int year,month,day,A,B,C,sum;
printf("input year,month,day:\n");
scanf("%d%d%d",&year,&month,&day);
A=f(sum,month);
B=year-1+(year-1)/4+(year-1)/400-(