初一 数学 因式分解 请详细解答,谢谢! (2 10:28:15)

(x-2)(x+3)+2(x+6)(x-5)-3(x^2-7x+12)
=(x^2+x-6)+2(x^2+x-30)-3(x^2-7x+12)
=(x^2+x-6)+(2x^2+2x-60)-(3x^2-21x+36)
=(x^2+x-6+2x^2+2x-60)-(3x^2-21x+36)
=(3x^2+3x-66)-(3x^2-21x+36)
=3x-66+21x-36
=24x-102
=2(12x-51)

(x-2)(x+3)+2(X+6)(x-5)-3(x2-7x+12)
=(x^2+x-6)+2(x^2+x-30)-3(x2-7x+12)
=24x-102
=2(12x-51)

全部分解
原式=x^2+x-6+2x^2+2x-60-3x^2+21x-36
=24x-102
=6(4x-17)

(x-2)(x+3)+2(X+6)(x-5)-3(x2-7x+12)
=(x-2)(x+3)+2(X+6)(x-5)-3(x-2)(x-5)
=(x-2)[(x+3)-(x-5)]+2(x-5)[(x+6)-(x-2)]
=8(x-2)+16(x-5)
=24x-96
=24(x-4)

(x-2)(x+3)+2(X+6)(x-5)-3(x2-7x+12)

= x^2+x-6+2x^2+2x-60-3x^2+21x-36

=24x-102

=2(12x-51)

估计提抄错了