Servlet中的NULLPOINTEREXCEPTION问题
来源:百度知道 编辑:UC知道 时间:2024/06/30 08:49:09
********************************************************************
import java.io.IOException;
import javax.servlet.*;
import javax.servlet.http.*;
import java.sql.*;
public class changeServlet extends HttpServlet
{
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
Connection conn = null;
Statement stmt = null;
ResultSet rs = null;
PlayerAccess accessConnection = new PlayerAccess();
//String target="/Update.jsp";
try
{
conn = accessConnection.getConnection();
stmt = conn.createStatement();
rs=stmt.executeQuery("select * from PlayerDetails where PlayerName="+(String)request.getParameter("PlayerName"));
while(rs.next())
{
stmt.executeUpdate("update PlayerDetails set PlayerName='"+(Str
import java.io.IOException;
import javax.servlet.*;
import javax.servlet.http.*;
import java.sql.*;
public class changeServlet extends HttpServlet
{
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
Connection conn = null;
Statement stmt = null;
ResultSet rs = null;
PlayerAccess accessConnection = new PlayerAccess();
//String target="/Update.jsp";
try
{
conn = accessConnection.getConnection();
stmt = conn.createStatement();
rs=stmt.executeQuery("select * from PlayerDetails where PlayerName="+(String)request.getParameter("PlayerName"));
while(rs.next())
{
stmt.executeUpdate("update PlayerDetails set PlayerName='"+(Str
accessConnection.close(conn, stmt, rs);
PlayerAccess.close(PlayerAccess.java:30)
将你的类PlayerAccess的代码页放出来吧..异常抛在这个类的第30行代码.
这个类的close(conn, stmt, rs)方法.
很有可能是conn,stmt,rs这三个中的参数有一个为空了.
补充:
第30行代码是哪句话了?