UC知道英文奥林匹克数学题！
来源：百度知道 编辑：UC知道 时间：2024/09/23 11:25:42
1.The digits of a 2-digit number are the same.When you multiply this number by 99, you get a 4-digit number in which the third digit (the number of tens) is 5. What number did you get after the multiplication?
2.In a running race there were 12 racers marked with numbers. What was their order at the finish line if, for every racer, the product of the racing number and the place-number the runner finished at was one more than a number divisble by 13?
翻译+答案
2.In a running race there were 12 racers marked with numbers. What was their order at the finish line if, for every racer, the product of the racing number and the place-number the runner finished at was one more than a number divisble by 13?
翻译+答案
1.一个个位和十位数字相同的两位数，当你将其乘以99时，你得到一个十位为5的四位数。请问乘出的数是多少？
解答：很简单啊。穷举就可以了。最后原两位数为44，乘出的数为4356。
2.一场跑步赛有12位选手标有不同的号码。到达终点时，如果他们的号码和他们的名次满足这样的关系：对每一位选手，他的号码和名次成绩乘积都比一个13的倍数大1，那么他们各自的名次应该是多少？
解答：翻译过来就简单了嘛。显然应该是（从1号到12号分别是）：1，7，9，10，8，11，2，5，3，4，6，12
第二题附vb穷举的程序
对于答案的唯一性，数学上有严格证明，就不在此赘述了
祝你答得开心~
vb程序：
For i = 1 To 12
For j = 1 To 12
If i * j Mod 13 = 1 Then Text1 = Text1 & "," & Str$(j) & " "
Next
Next
1.一个个十位相同的两位数*99以后的一个四位数，其十位为5，则这个四位数是多少？
答案：4356=44*99
2.在一个按顺序编号的12名赛跑手比赛中，若对于每名赛跑手来说，他在终点处取得的名次与其自己的编号相乘所得除以13后均余1，求赛跑手们对应的名次？
答案：
加分给答案