about magnetic flux

来源：百度知道 编辑：UC知道 时间：2024/07/02 22:41:43
A loudspeaker magnet has a circular air-gap of inner diameter d1=22mm, outer diameter d2=24mm , and depth h=8mm to accommodate the oscillation coil. If the air-gap has magnetic flux density B=0.75Wb/m2 , find the magnetic flux that must be produced for a flux leakage of 15%.

答案是 498.6μWb
我不理解题意 答案绝对没错 谁能告诉我一下是怎麼求出来的啊~~~

扬声器磁体有一个圆形气隙内径蛋白D1 = 22毫米，外径D2类= 24毫米，和深度h = 8毫米，以适应振荡线圈。如果气隙的磁通密度乙= 0.75Wb/m2 ，找到磁通量必须制作的漏磁的15 ％ 。