UC知道数列递推公式求通项
来源：百度知道 编辑：UC知道 时间：2024/06/30 16:14:02
A(n+1)=(n+1)An+1 怎么求通项，高手指点下
A1=1
或者告诉我这个怎么求和
(n+1)*n*(n-1)``````````````1+
(n+1)*n*`````````````````2+
(n+1)*n*``````````````3+
````````````````````
(n+1)*n+
(n+1)
A1=1
或者告诉我这个怎么求和
(n+1)*n*(n-1)``````````````1+
(n+1)*n*`````````````````2+
(n+1)*n*``````````````3+
````````````````````
(n+1)*n+
(n+1)
迭代法。 楼上花了功法，但是不对，如果是A(n+1)+1/(n+1)=(n+1)[An+(1/n)]倒还可以构造Bn={An+1/n}，但也不是等比数列啊。
首项知道不？
先等式两边同加1/n
化简后得
A(n+1)+1/n=(n+1)[An+(1/n)]
设Bn={An+1/n}
则Bn为公比为n+1的等比公式
由A1求出B1
再求Bn的通向公式为Bn=B1*[（n+1）^(n-1)]
则An=Bn-1/n