（1-根号3）的平方-2/（根号3+1）+1

1、：（1-根号3）的平方-2/（根号3+1）+1
=(1-2根号3+3)-2（根号3-1)/(3-1)+1
=4-2根号3-根号3+1+1
=6-3根号3

2.x的平方/（x的平方+3x+2）-1/（x的平方-x-2）除以1/（x的平方-4）
=x^2/[(x+2)(x+1)]-（x^2-4)/(x^2-x-2）
=x^2/[(x+2)(x+1)]-[（x-2)(x+2)]/[(x-2)(x+1)]
=x^2/[(x+2)(x+1)]-（x+2)/(x+1)
=[x^2-(x+2)^2]/[(x+2)(x+1)]
=[(x-x-2)(x+x+2)]/[(x+2)(x+1)]
=-4(x+1)/[(x+2)(x+1)]
=-4/(x+2)

1.原式=(1-√3)²-2/(√3+1)+1
=1-2√3+3-2(√3-1)/2+1
=5-2√3-√3+1
=6-3√3
2.原式=x²/(x²+3x+2)-[1/(x²-x-2)]/[1/(x²-4)]
=x²/(x²+3x+2)-(x²-4)/(x²-x-2)
=x²/[(x+1)(x+2)]-(x+2)(x-2)/[(x-2)(x+1)]
=x²/[(x+1)(x+2)]-(x+2)/(x+1)
=[x²-(x+2)²]/[(x+1)(x+2)]
=(-2)(2x+2)/[(x+1)(x+2)]
=-4(x+1)/[(x+1)(x+2)]
=-4/(x+2)