1/(2×4)+1/(4×6)+1/(6×8)+1/(8×10)+1/(10×12)+1/(12×14)+。。。。。。+1/(98×100)=
来源:百度知道 编辑:UC知道 时间:2024/09/23 17:16:26
=1/2[(1/2-1/4) + (1/4 -1/8) + ... + (1/98-1/100)]=1/2(1/2-1/100)=49/200
1/(2*4)=(1/2-1/4)/2,1/(4*6)=(1/4-1/6)/2,以此类推啦,然后提取个1/2啦
,可以抵消的啦。注意利用这个公式就好------d/n(n+m)=d/m(1/n-1/n+m)
(2/1+3/1+4/1+5/1)乘(2/1+3/1+4/1+5/1+6/1)减(2/1+3/1+4/1+5/1+6/1)乘(2/1+3/1+4/1+5/1)等于多少
求解(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
计算(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
计算1/(1*3)+1/(2*4)+...+1/[n+(n+2)]
(1-1/2^2)(1-1/3^2)(1-1/4^2)......(1-1/99^2)(1-1/100^2)
(9-1/2)×(1+1/2)×(1-1/3)×(1-1/4)×(1+1/4)×┈×(1-1/2005)×(1-1/2006)怎么做??
(1+1/2+1/3+1/4)×
8,8,4,1/4,2,2,2,1/2,(),()
计算1+1/2+(1/3-1)+1/4+1/5+(1/6-1/2)+1/7+1/8+(1/9/1/3)......
1+1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+.....+1/(1+2+3+...+100)=?