1.03的24次方是多少

2.03279410646------

幂次方公式(a+b)^n=[Cn/n*a^n*b^(n-n)]+[(Cn-1/n)*a^(n-1)*b^(n-(n-1))]...[Cn-n/n*a^(n-n)*b^-(n-n)],Cn/n是C上底n下底n
1.03^24=(1+0.03)^24=(c24/24)*1^24*0.03^(24-24)+。。。+c0/24*1^0*0.03^24=1+0.72+0.2484+0.0546+0.0086+0.0010+0.0001+0+0+...+0=2.0327

1.03^24=(1+0.03)^24
≈1+C(24,1)*0.03+C(24,2)*0.03^2+C(24,3)*0.03^3+C(24,4)*0.03^4
≈1+0.72+0.25+0.05+0.01
=2.03
注：C(24,n)为组合数

2.0328