circle类和table类派生roundtable类
来源:百度知道 编辑:UC知道 时间:2024/09/22 16:48:23
#include <iostream.h>
#define PAI 3.14
class table
{
public:
double GaoDu;
char *YanSe;
public:
virtual void display()=0;
};
class circle
{
public:
double BanJing;
public:
virtual void display()=0;
};
class roundtable : public table,public circle
{
public:
void iniroundtable(double G,double B,char *Y)
{
GaoDu=G;
BanJing=B;
YanSe=Y;
}
void display()
{
cout<<"Yuan Zhuo de GaoDu : "<<GaoDu<<endl;
cout<<"Yuan Zhuo de YanSe : "<<YanSe<<endl;
cout<<"Yuan Zhuo de MianJi : "<<PAI*BanJing*BanJing<<endl;
}
protected:
double GaoDu,BanJing;
char *YanSe;
};
int main()
{
double G,B;
char *Y;
cout<<"Shu Ru Yuan De BanJing :";
cin>>B;
cout<<"Shu
#define PAI 3.14
class table
{
public:
double GaoDu;
char *YanSe;
public:
virtual void display()=0;
};
class circle
{
public:
double BanJing;
public:
virtual void display()=0;
};
class roundtable : public table,public circle
{
public:
void iniroundtable(double G,double B,char *Y)
{
GaoDu=G;
BanJing=B;
YanSe=Y;
}
void display()
{
cout<<"Yuan Zhuo de GaoDu : "<<GaoDu<<endl;
cout<<"Yuan Zhuo de YanSe : "<<YanSe<<endl;
cout<<"Yuan Zhuo de MianJi : "<<PAI*BanJing*BanJing<<endl;
}
protected:
double GaoDu,BanJing;
char *YanSe;
};
int main()
{
double G,B;
char *Y;
cout<<"Shu Ru Yuan De BanJing :";
cin>>B;
cout<<"Shu
不能通过指针为字符串赋值吧。
看不懂你写这个程序的意图,既然用的继承,何必roundtable类又声明继承过来的成员呢?
分析你的目的,可将程序写成:
#include <iostream>
#include <string>
using namespace std;
#define PAI 3.14
class roundtable
{
public:
void iniroundtable(double G,double B,string Y)
{
GaoDu=G;
BanJing=B;
YanSe=Y;
}
void display()
{
cout<<"Yuan Zhuo de GaoDu : "<<GaoDu<<endl;
cout<<"Yuan Zhuo de YanSe : "<<YanSe<<endl;
cout<<"Yuan Zhuo de MianJi : "<<PAI*BanJing*BanJing<<endl;
}
protected:
double GaoDu,BanJing;
string YanSe;
};
int main()
{
double G,B;
string Y;
cout<<"Shu Ru Yuan De BanJing :";
cin>>B;
cout<<"Shu Ru Zhuo De GaoDu :";
cin>>G;
cout<<"Shu Ru Zhuo De YanSe :";
cin>
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请问:round和circle的区别