微机原理汇编语言问题，哪位高手帮忙解决下？要求写出程序注释，并把源程序改为任意两个六位十进制相加。

来源：百度知道 编辑：UC知道 时间：2024/09/21 16:35:55
CRLF MACRO
MOV DL,0DH
MOV AH,02H
INT 21H
MOV DL,0AH
MOV AH,02H
INT 21H
ENDM
DATA SEGMENT
DATA1 DB 33H,39H,31H,37H,34H
DATA2 DB 36H,35H,30H,38H,32H
DATA ENDS
STACK SEGMENT
STA DB 20 DUP(?)
TOP EQU LENGTH STA
STACK ENDS
CODE SEGMENT
ASSUME CS:CODE,DS:DATA,SS:STACK,ES:DATA
START： MOV AX,DATA
MOV DS,AX
MOV AX,STACK
MOV SS,AX
MOV AX,TOP
MOV SP,AX
MOV SI,OFFSET DATA2
MOV BX,05
CALL DISPL
CRLF
MOV SI,OFFSET

;整个程序实现data1和data2的相加
CRLF MACRO;宏定义回车换行
MOV DL,0DH
MOV AH,02H
INT 21H
MOV DL,0AH
MOV AH,02H
INT 21H
ENDM
DATA SEGMENT;data1和data2为加数和被加数
DATA1 DB 33H,39H,31H,37H,34H
DATA2 DB 36H,35H,30H,38H,32H
DATA ENDS
STACK SEGMENT
STA DB 20 DUP(?)
TOP EQU LENGTH STA;把sta的长度给top
STACK ENDS
CODE SEGMENT
ASSUME CS:CODE,DS:DATA,SS:STACK,ES:DATA
start: MOV AX,DATA
MOV DS,AX
MOV AX,STACK
MOV SS,AX
MOV AX,TOP
MOV SP,AX
MOV SI,OFFSET DATA2;把data2的偏移量给si
MOV BX,05;初始bx，输出五个字符