编写一个程序输出1~100之间所有被7除余2的数

什么语言?批处理也能完成
@echo off&setlocal enabledelayedexpansion
for /l %%i in (1,1,100) do (
set var=%%i
set /a mod=!var!%%7
if !mod!==2 (
set /p tmp=%%i,<nul
)
)
pause>nul
-------------------------
i = 1
Do Until i > 100
If (i Mod 7 = 2) Then
Print i
End If
i = i + 1
Loop

#define a 7
int i,b;
for(i=1;i<101;i++)
{
b=i%a
if (b==2)
printf("Num=%d\n",b)
}