x3-6x+5如何分解因式

x3-6x+5
=x3+x2-6x+5-x2
=x3+(x-3)2-4-x2
=x3+(x-3-2)(x-3+2)-x2
=x3-x2+(x-5)(x-1)
=x2(x-1)+(x-5)(x-1)
=（x-1)(x2+x-5)

OK,就是这样,应该看得懂吧

x3-6x+5=X^3-X^2+X^2-6X+5=(X-1)*X^2+(X-1)*(X-5)
=(X-1)(X^2+X-5)

x3-6x+5=x3-6x+6-1=x3-1-6(x-1)
=(x-1)(x2+x+1)-6(x-1)
=(x-1)(x2+x+1-6)
=(x-1)(x2+x-5)

x3-6x+5

=(x^3-x)-(5x-5)

=x(x^2-1)-5(x-1)

=x(x+1)(x-1)-5(x-1)

=(x-1)(x^2+x-5)

=(x-1)(x2+x-5)

x^3-x^2+x^2-6x+5
=x^2(x-1)+(x-5)(x-1)
=(x-1)(x^2+x-5)
我想你一定是不明白十字相乘
X^2-6X+5

X 1 1X5=5 1xX+5xX=6X
X 5
因为1次项为负所以=(X-1)(X-5)
你可以问问你的老师十字相乘