数学问题...急忙

来源:百度知道 编辑:UC知道 时间:2024/07/04 00:50:07
1/(1*2)+1/(2*3)+.....1/(98*99)

原式=(2-1)/1*2+(3-2)/2*3+……+(99-98)/98*99
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+……+(1/98-1/99)
=1-1/99
=98/99

1/(1*2)=1/1-1/2
1/(2*3)=1/2-1/3
.....
.....
1/(98*99)=1/98-1/99
1/(1*2)+1/(2*3)+.....1/(98*99)=(1/1-1/2)+(1/2-1/3)+1/3-1/4+....+(1/98-1/99)

然后好多式子就约掉了,最后只剩下1/1-1/99=98/99

1/1*2=1-1/2
1/2*3=1/2-1/3
...
1/98*99=1/98-1/99
1/(1*2)+1/(2*3)+.....1/(98*99)
=1-1/99=98/99

1/(1*2)+1/(2*3)+.....1/(98*99)
= 1-1/2+1/2-1/3+1/3-1/4+......+1/98-1/99
= 1-1/99
=98/99