UC知道求助呀,帮帮我,这怎么翻译成英语呀
来源：百度知道 编辑：UC知道 时间：2024/09/20 07:01:41
2电源启动电流选择0.5－3mA，功率管的放大倍数可按10计算，则启动电阻选择应保证电源启动时功率管基极电流为0.05-0.3mA，因此，可10倍减少启动电阻的功耗，降低了待机功耗
The 1 a switch of the anti- arouse type electric current control power supplies design, don't continue( or low pressure shallow consecution) the electric current work mode.
The 2 power supplies start the electric current to choose 0.53 mAses of －s, the power take care of of enlarge the multiple and can press 10 calculation, then start the electric resistance choice and should guarantee the power supply start the power take care of 基 pole electric current is 0.05-0.3 mAs, therefore, can 1000% decrease start the 功 of the electric resistance consume, lowering to need the machine 功 to consume
1.Instead stirring up -like electric current control switching powersupply design, not continuously (or when low pressure is shallowcontinuously) the electric current working pattern.
2.The power source starting current chooses 0.5 - 3mA, the power tubeenlargement factor may according to 10 computations, then the startingresistance choice should guarantee the power sourc