一道复数问题

x^5=32=32(cos0°+isin0°),
x=2[cos(k*360°+0°)/5+isin(k*360°+0°)/5](k=0,1,2,3,4)
k=0:x1=2
k=1:x2=2[cos72°+isin72°)
k=2:x3=2[cos144°+isin144°)
k=3:x4=2[cos216°+isin216°)
k=4:x5=2[cos288°+isin288°)

你是不是有神经！10分还要步骤！

10分还要步骤???

1*5165491274*524+952+5+9432

x^5=32
32=2^5*(cos0＋isin0）
所以x=(2^5*(cos0+isin0))^1/5
x=2(cos((0+2nπ)/5)+isin((0+2nπ)/5))
n=0,1,2,3,4
得5个根
x1=2
x2=2(cos(2π/5)+isin(2π/5))
x3=2(cos(4π/5)+isin(4π/5))
x4=2(cos(6π/5)+isin(6π/5))
x5=2(cos(8π/5)+isin(8π/5))