x+y+z=xyz的所有正整数解（急需）

x=1,y=2,z=3
#include "stdio.h"
main()
{
int x;
int y;
int z;

for (x=1;x<1000;x++)
{
for (y=1;y<1000;y++)
{
for (z=1;z<1000;z++)
{
if (x==(x*y*z)-y-z)
{printf ("%d",x);
printf("\n");
printf("%d",y);
printf("\n");
printf("%d",z);
printf("\n");

}

}
}
}

for x=1 to 1e+32
for y=1 to 1e+32
for z=1 to 1e+32
if x+y+z =x*y*z then print x;"+";y;"+";z;"=";x;"*";y;"*";z,
next z
next y
next x
end

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