Data dimensions must agree .求助MATLAB高手

来源：百度知道 编辑：UC知道 时间：2024/09/28 15:09:13
今天老师布置了一道MATLAB题，用迭代法求金属槽内电位分布。
程序如下
%Part 1: Initializing data;
Nx=4;
Ny=2;
Lx=4;
Ly=2;
Hx=Lx/Nx;
Hy=Ly/Ny;
alpha=1.17;
Nmax=160;
u=zeros(Nx+1,Ny+1);
%Part 2: Calculating coordinates for each point and applying loads at boundary;
x0=0;
y0=0;
for j=1:(Ny+1)
for i=1:(Nx+1)
k=(j-1)*(Ny+1)+i;
x(k)=x0+Hx*(i-1);
y(k)=y0+Hy*(j-1);
if abs(y(k)-y0)<1e-05
u(j,i)=0;
end;
if abs(x(k)-x0)<1e-05
u(j,i)=0;
end;
if abs(x(k)-x0-Lx)<1e-05
u(j,i)=0;
end;
if abs(y(k)-y0-Ly)<1e-05
u(j,i)=100;
end;
end;
end;
%Part 3: Calculating potential with iterating method;
Error_max=0;
Precision=1e-05;
for k=1:Nmax
Error_max=0;
for i=2:Ny
for j=2:Nx
u1=u(i,j);
u(i,j)=u(i,j)+alpha*(u(i+1,j)+u(i,j+1)+u(i-1,

X、Y与u的大小不同。

>> whos
Name Size Bytes Class Attributes

X 3x5 120 double
Y 3x5 120 double

u 5x5 200 double

>> X

X =

0 1 2 3 4
0 1 2 3 4
0 1 2 3 4

>> Y

Y =

0 0 0 0 0
1 1 1 1 1
2 2 2 2 2

>> u

u =

0 0 0 0 0
0 35.7143 42.8571 35.7143 0
100.0000 100.0000 100.0000 100.0000 100.0000
0 0 0 0 0
0 0 0 0 0