编程统计数列1/(n+1)的前100项之和（其中n=1、2.....100）。要详细过程,谢谢啦大家~帮帮我

这个也太简单了...用C可以吧...
int n;
double sum;
n=sum=0;
while (n<=100)
{
n++;
sum=1/(n+1);
}
printf ("%d",sum);

main()
{
int i=1;
double s=0.0;
for(;i<101;s+=(1.0/(i+1)),i++);
printf("%f\n",s);
}

dim i as long ,count as double
for i=1 to 100
count=count+1/(i+1)
next i